F(x^2-2x+12)=3x^2-6x+28

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Solution for F(x^2-2x+12)=3x^2-6x+28 equation: 



(F^2-2F+12)=3F^2-6F+28

We move all terms to the left:

(F^2-2F+12)-(3F^2-6F+28)=0

We get rid of parentheses

F^2-3F^2-2F+6F+12-28=0

We add all the numbers together, and all the variables

-2F^2+4F-16=0

a = -2; b = 4; c = -16;
Δ = b2-4ac
Δ = 42-4·(-2)·(-16)
Δ = -112
Delta is less than zero, so there is no solution for the equation

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